Question

What value of k makes the trinomial x^2 - 10x + k a perfect square?
*Show your work*

Answer 1

Answer:

${x}^{2} - 10x + k = \\ {x}^{2} - 2 \times x \times 5 + {5}^{2} + k - {5}^{2} = \\ {(x - 5)}^{2} + k - 25$

for perfect square, k–25 = 0

so k = 25

Ans.