what value of p 3x square -2x+p square-4=0 one root be 0
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Answer :
p = ±2
Step-by-step explanation :
➤ Quadratic Polynomials :
✯ It is a polynomial of degree 2
✯ General form :
ax² + bx + c = 0
✯ Determinant, D = b² - 4ac
✯ Based on the value of Determinant, we can define the nature of roots.
D > 0 ; real and unequal roots
D = 0 ; real and equal roots
D < 0 ; no real roots i.e., imaginary
✯ Relationship between zeroes and coefficients :
✩ Sum of zeroes = -b/a
✩ Product of zeroes = c/a
________________________________
Given,
- quadratic equation,
3x² - 2x + p² - 4 = 0
- One root = 0
Since, 0 is a root;
substitute x = 0, the result is zero.
Put x = 0,
3(0)² - 2(0) + p² - 4 = 0
3(0) - 0 + p² - 4 = 0
0 - 0 + p² - 4 = 0
p² - 4 = 0
p² = 4
p = √4
p = ±2
Therefore, p = +2 , -2
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