Question

what value of p are 2 p + 1,13, 5p - 3 three consecutive terms of an Ap?​

Answer 1

Answer:

Given 2p+1, 13 , 5p-3 are in AP.

To find: value of P

If a,b,c are in AP then we know that

2b=( a+c)

Here a= 2p+1

b=13

c=5p-3

2 (13) =(2p+1+5p-3)

26=7p-2

26+2=7p

28=7p

p=28/7 =4

Therefore the value of

P is 4.

Answer 2

Answer:

Solution:

Given 2p+1, 13 , 5p-3 are in AP.

To find: value of P

If a,b,c are in AP then we know that

2b=( a+c)

Here a= 2p+1

b=13

c=5p-3

2 (13) =(2p+1+5p-3)

26=7p-2

26+2=7p

28=7p

p=28/7 =4

Therefore the value of

P is 4.

hope its help u...........xd