Question

What value of s makes the following equation true?

s3=−343

Enter your answer as a number, like this: 42

Answer 1

Answer:

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Step-by-step explanation:

114.3

Answer 2

Answer: s = $\frac{-7-7i\sqrt{3} }{2}$ = -3.5000-6.062i

s =

is the equation makes satisfies the

equation

  $s^3-343 = 0$

Step-by-step explanation:

Now here the equation is

 $s^3-343 = 0$                     ...................(1)

Therefore we know that,

$a^3-b^3 = (a - b)(a^2 +ab+b^2)$          ..............(2)

From equations (1) and (2),

we get,

$s^3 - 7^3 = (s - 7)(s^2 + 7s + 7^2)$

From the above equation, we got one root (s -7)

Now for the $(s^2+7s+7^2)$    ......................(3)

Let's do the factor method for the root

Therefore,

By using the Formula method for the quadratic equation,

the formula for the quadratic equation is

root = $\frac{-b+- \sqrt{b^{2} -4ac} }{2a}$            .......................(4)

Now from the equation(3) and (4) we get,

root = $\frac{\sqrt{7^{2}-4 X 1 X49 } }{2X1}$

$= \frac{-7+-\sqrt{49 - 196}}{2X1}$

$= \frac{-7+-\sqrt{-147} }{2}$

Here we get,

$\frac{-7+-i7\sqrt{3} }{2}$

After solving the above equation we get the root of