What value of thyl alcohol and water must be mixed together to prepare 250ml of 60% by volume oof alcohol in water?
Answers
Answered by
0
To prepare 250ml means to prepare 250 g let it
Ethyl alcohol(C2H5OH) mass=36
Mass of Water(H20)= 18
Mass of Ethyl alcohol should be
60%=Mass of Ethyl alcohol/Mass of volume of solution
60%=M/250
60×250/100= M
150g=M
means 150 ml of Ethyl alcohol and 100 ml of water
Ethyl alcohol(C2H5OH) mass=36
Mass of Water(H20)= 18
Mass of Ethyl alcohol should be
60%=Mass of Ethyl alcohol/Mass of volume of solution
60%=M/250
60×250/100= M
150g=M
means 150 ml of Ethyl alcohol and 100 ml of water
Similar questions