what value of x would make AOB a line angle AOC is 4x angle BOC 6x+30°
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Answer:
x = 15°
Step-by-step explanation:
Given-- ∠AOC = 4x, ∠BOC = 6x +30°
so, if the required condition is to make it a straight line, ∠AOB = 180°
Thus, ∠AOC + ∠BOC = 180°
4x + 6x + 30° = 180°
10x = 180° - 30°
x = 150°/10
x = 15°
Thus, x has to be 15° to make AOB a line!
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