Question

What value of y is the expression 3y2- 3y - 18 = 0

Answer 1

Required Answer:-

Correct Question:

• Find the values if y in the equation 3y² - 3y - 18 = 0

Solution:

Given that,

→ 3y² - 3y - 18 = 0

Taking 3 as common, we get,

→ 3(y² - y - 6) = 0

Dividing 3 from both sides, we get,

→ y² - y - 6 = 0

→ -3 × 2 = -6 and -3 + 2 = -1

→ y² - 3y + 2y - 6 = 0

→ y(y - 3) + 2(y - 3) = 0

→ (y + 2)(y - 3) = 0

Therefore,

→ Either (y + 2) = 0 or (y - 3) = 0

→ y = 3, -2

Answer:

• y = 3, -2

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Answer 2

Given Equation:-

$\red{ \boxed{ \sf3 {y}^{2} - 3y - 18 = 0}}$

Step-by-step explanation:-

$\dashrightarrow \: \sf3 {y}^{2} - 3y - 18 = 0$

$\dashrightarrow \: \sf3 {y}^{2} - 9y + 6y- 18 = 0$

(Spitting the middle term )

$\dashrightarrow \: \sf \{3 {y}^{2} - 9y \} + \{ 6y- 18 \}= 0$

$\dashrightarrow \: \sf 3y\{{y}- 3 \} + 6\{ y- 2\}= 0$

$\dashrightarrow \: \sf \{3y + 6 \}\{ y- 2\}= 0$

Comparing

Value of y is :-

• 3y + 6 = 0

• 3y = -6

• y = -6/3

• y = -2

Or

• y - 2 = 0

• y = 2