Question

What value should 'a' posses. So that x+1
may be a factor of polynomial P(x) = 2x²-ax-(2a-3)x+2
​

Answer 1

Answer:if x+1 should be the factor of p(x) , then p(x) must be equal to zero..

So we get,

x+1=0

x=-1

Putting x= -1 value in p(x).... We get,

P(-1) =2(-1) ^2-a(-1)-(2a-3)(-1)+2

P(-1) = 2+a-(-1) (2a-3) +2

P(-1) =2+a-(-2a+3) +2

P(-1) =2+a+2a-3+2

P(-1) =1+3a..... (1)

Since, we know that x+1 should be the factor of P(x), we get....

P(-1) =0

So,

1+3a=0...... From eq(1)

3a= -1

a= -1/3

See and understand the simplification properly....

Step-by-step explanation: