Question

What values can A+B take if Cos²A=Cos²B?​

Answer 1

Answer:

$</p><p></p><p>=12(cos2A−cos2B)</p><p></p><p>Explanation:</p><p></p><p>cos2A=12(1+cos2A)</p><p>cos2B=12(1+cos2B)</p><p></p><p>Thus,</p><p></p><p>cos2A−cos2B=12(1+cos2A)−12(1+cos2B)</p><p></p><p>=12(1+cos2A−1−cos2B)</p><p>=12(cos2A−cos2B)</p><p></p><p>$

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Answer 2

Answer:

For quick solution, evaluate the expression with A=0; B=60

cos2(0)+cos2(60)−cos(0)cos(60)=3/4cos2(0)+cos2(60)−cos(0)cos(60)=3/4

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