Question

What values of a and b make the given statement
true ?
(ay2 + 3xy - 9x2)-(-4y2 + 8xy + bx2)
1
= 10y2 – 5xy - 10x2
Bond.
Wherever 2 is written it means square ​

Answer 1

Answer:

a+4=10

=>a=6

and -9-b = -10

=> b = 1

Answer 2

(ay2+3xy−9x2)−(4y2+8xy+bx2)=10y2−5xy−10x2

Which simplifies to

ay2−4y2+3xy−8xy−9x2−bx2=10y2−5xy−10x2

On the left hand side, factor out common terms.

(a−4)y2−5xy−(9+b)x2=10y2−5xy−10x2

Since there appears to be a −5xy on both sides, we can remove them for simplicity.

(a−4)y2−(9+b)x2=10y2−10x2

So then

a−4=10,9+b=10⟹a=14,b=1

We got the equations by comparing the coefficients of the y2 and x2 terms on both sides.