what vector added to(2i-2j+k) and (2i-k) will give a unit vector along negative y axis
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Answer:
(2
i
^
−2
j
^
+
k
^
)+(2
i
^
−
k
^
)=(4
i
^
−2
j
^
+0
k
^
)
Now we have to find a vector which when added to the above vector gives along negative y-axis i.e. −
j
^
.
Let the required vector be x
i
^
+y
j
^
+z
k
^
⇒(4
i
^
−2
j
^
+0
k
^
)+(x
i
^
+y
j
^
+z
k
^
)=−
j
^
⇒(4+x)
i
^
+(−2+y)
j
^
+(0+z)
k
^
4+x=0⇒x=−4
−2+y=−1⇒y=1
0+z=0⇒z=0
Therefore the required vector is −4
i
^
+
j
^
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