Question

What volume at N.T.P is occupied by 6.023 x 1021 molecules of oxygen?
Pls answer fast...

Answer 1

22.4x10-2Answer:

Explanation:

i mol=22.4l=6.022x1023

one particle=22.4/6.022x1023

6.022x1021particle=22.4x6.022x1021/(6.022x1023)

                               =22.4/100L

                               =224ml