Question

What volume at n.t.p of ammonia gas will be required to be passed into 30 ml of N h2so4 solution to bring down the acid normality to 0.2N?

Answer 1

MEQ  OF original H2SO4 = 30*1 = 30
MEQ of H2SO4 after passing NH3=30*0.2
MEQ of NH3 passed = MEQ of h2so4 lost w/17 * 1000 = 24
WNH3 = 0.408g
hence vol of NH3 at STP = (22.4 * 0.408)/17
0.5376l
i.e.,537.6ml

Answer 2

Answer:537.6 ml

Explanation:

Meq of original H2SO4=30×1=30

Meq of H2SO4 after passing NH3=30×0.2=6

Meq of H2SO4 lost =30−6=24

Meq of NH3 passed=Meq of H2SO4 lost

w17×1000=24

WNH3=0.408g

∴ Volume of NH3 at STP=22.4×0.40817

⇒0.5376l

⇒537.6ml