Question

what volume at STP get occupy by 1000 g of co2​

Answer 1

Answer:

I hope it helps

Explanation:

CO2 has a molecular weight of 44 g/mol 1 kg CO2 = 1000 g × (1 mol/44 g) = 22.7 mol CO2 V=nRT/P, V=(22.7)(0.0821)(300)/1 = 559 L CO2 at 27°C (300K), 1 atm This is a little more than half a cubic meter approximately equal to the volume of two bathtubs or the trunk of a large car.