what volume do 2.5 mol of ammonia, NH3 occupy under standard conditions?
Answers
Answer:
Radius of hydrogen atom, r = 0.5 Å = 0.5 × 10-10 m
Volume of hydrogen atom = (4/3) π r3
= (4/3) × (22/7) × (0.5 × 10-10)3
= 0.524 × 10-30 m3
Now, 1 mole of hydrogen contains 6.023 × 1023 hydrogen atoms.
∴ Volume of 1 mole of hydrogen atoms, Va = 6.023 × 1023 × 0.524 × 10–30
= 3.16 × 10–7 m3
Molar volume of 1 mole of hydrogen atoms at STP,
Vm = 22.4 L = 22.4 × 10–3 m3
∴
V
a
V
m
=
3.6×10
−7
22.4×10
−3
=7.08×10
4
Hence, the molar volume is 7.08 × 104 times higher than the atomic volume.
The ratio is so large because inter-atomic separation in hydrogen gas is large.
Answered By
Answer:
Hope this helps you
Explanation:
Treat both gases as ideal and use the ideal gas equation. Note that idealization of gases is not always justified, but here, with moderate pressures (1 atm) and moderate temperatures, it is entirely reasonable.
Explanation:
V
=
n
R
T
P
. Use an appropriate gas constant,
R
, i.e.
8.314
J
K
−
1
m
o
l
−
1
. All you need to do is calculate the moles of each gas, dihydrogen, and of ammonia, and plug the numbers in. Remember that you have to use absolute temperature, that is Celsius temperature + 273.15.