Question

what volume does 400cm3 of gas sample will occupy if pressure changes from 760torr to 3 atm?​

Answer 1

Answer:

This is an ideal gas question. The idea gas law is:

PV = nRT

As far as the question goes, we are only worried about the change in volume given an initial and final pressure and an initial volume. So, use the following proportion:

P(1)*V(1) = P(2)* V(2)

Where P(1) (760 torr or 1 atm) is the initial pressure, P(2) the final pressure (3 atm), V(1) is the initial volume (400 cm3 or 400 mL) and V(2) the final volume, the number we are after. So:

V(2) = P(1) * V(1) / P2 = 1 * 400 mL / 3 = 400 mL/3 = 133.33 mL

Answer 2

Answer:

The gas will occupy an volume of 133.33L if pressure changes from 760torr to 3atm.

Explanation:

Given that,

The initial volume of the gas is $V_{1}=400cm^{3}$

Initial pressure of the gas is $P_{1}=760torr=1atm$

Final pressure of the gas is $P_{2}=3atm$

We are required to find the final volume of gas which can be found using Boyle`s Law.It states that the pressure of an ideal gas is inversely proportional to its volume.Therefore,it can be mathematically written as follows-

$P\propto\frac{1}{V} = > P_{1} V_{1} =P_{2} V_{2}$

Substituting the given values in above relation we get

$1\times400=3V_{2}= > V_{2}=\frac{400}{3} =133.33L$

Therefore,the gas will occupy an volume of 133.33L if pressure changes from 760torr to 3atm.

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