Question

What volume is occupied at ntp by 1.4g of nitrogen?

Answer 1

Hey.

Here is the answer .

Mole = Volume/22.4 (At S.T.P or N.T.P.)

So according to this formula 1 Mole of any gas occupies 22.4 litres at N.T.P.

For Nitrogen gas 1 mole = 14g

so, for given 1.4 g = 1/14 × 1.4 = 0.1 mole

Since 1 mole occupies 22.4 L at NTP

so, 0.1 mole will occupy 22.4×0.1 L at NTP

Hence 1.4 g of Nitrogen gas occupy 2.24 L at NTP.

Thanks.

Answer 2

Answer:1.12litre

Explanation:28 g of nitrogen at NTP occupy volume 22.4l

1.4 g of nitrogen at NTP will occupy volume =22.4/28×1.4=1.12L