what volume is occupied at stp by 66.022×10^18 molecules of oxygen...ps im new to class 11th science do you have some tips for me ? you can also suggest me books
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Answer:
Explanation:
1 mole of oxygen contains 6.023x 10^23 molecules
1 mole = 22.4 litre
Therefore: volume occupied by 66.022x 10^18 molecules =
66.022x 10^18 x 22.4 / 6.023x10^23
=0.0024 litres
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pranvi2704:
You can go with book selina chemistry. ..I'm using it...
and we don't require temperature here.
thanks mate for your feedback i know that temps aren't required in this question but accoring to formula we do have to mention that our given volume in L is at stp(273k)
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