What volume is occupied by 0.25 mol of carbon dioxide gas at 25 °C and 371 torr?
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Answer: Volume = 12.48 lit.
Explanation: n = 0.25 mole
T = 25+273 = 298K
P = 375 torr [ 1 torr = 1 mm Hg ]
= 375 mm Hg
= 375/ 760
= 0.49 atm
We have, PV = nRT
V = nRT / P
By putting the values we get the value of V = 12.48 lit. ans
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