what volume is occupied by 10^24 molecules of nitrogen, oxygen and chlorine at STP ?
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2
Answer:
22.41
Explanation:
AT STP, 1 mole of any element / compound occupies 22.4l
∗ 14g of N
2
=0.5 mole of N
2
Molecular weight of N
2
=28g
∴ it occupies 22.4l×0.5=11.2l
∗ 22g of CO
2
molecular weight of CO
2
=12+2×16=44gm
∴ moles of CO
2
=
44
22
=0.5
∴ it occupies 0.5×22.4=11.2l
∗ 32g of SO
2
molecular weight of SO
2
=32+16×2=64g
∴ moles of SO
2
=
64
32
=0.5
∴ volume occupies =0.5×22.4=11.2l
∗ 32gm of O
2
molecular weight of O
2
=16×2=32g
∴ no. of moles of O
2
=
32
32
=1
∴ volume occupied =1×22.4=22.4l
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