Chemistry, asked by tanmay1992, 3 months ago


What volume (L) of O2 gas at 25 °C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)?​

Answers

Answered by siliverusanthosh
3

Answer:

moles KClO3 = 7.5 g/ 122.55 g/mol=0.061

moles O2 = 0.061 x3/2=0.0915

V = 0.0915 x 0.08206 x 298 K/ 1.00=2.24 L

Answered by syed2020ashaels
0

Answer: Volume= 2.24L

Explanation:

Antoine Lavoisier is widely known as the "Father of Modern Chemistry". He was one of the first to study chemical reactions in detail. As part of his studies on the composition of the atmosphere, Lavoisier allowed mercury to react with oxygen to form mercuric oxide. He was then able to demonstrate that the decomposition of mercuric oxide produces mercury and oxygen. The above diagram shows the apparatus used by Lavoisier to study the formation and decomposition of mercuric oxide.

A decomposition reaction is a reaction in which a compound breaks down into two or simpler substances. The general form of the decomposition reaction is:

AB→A+B

The simplest kind of decomposition reaction is when a binary compound breaks down into its elements. Mercury(II) oxide, a red solid, decomposes into mercury and oxygen gas when heated.

Moles KClO_{3} = 7.5 g/ 122.55 g/mol=0.061

moles O_{2} = 0.061*3/2=0.0915

V = 0.0915*0.08206*298 K/ 1.00=2.24 L

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