Question

What volume of 0.01 M sulfuric acid would have to be mixed with 250 mL of 0.02 M
sulfuric acid in order to neutralize 500 mL of 0.1 M sodium hydroxide?

Answer 1

Explanation:

know that :

N

1

V

1

=N

2

V

2

Normality=Molarity×Basicity

For sulphuric acid, the basicity is 2.

∴N

1

=0.1×2=0.2N

V

1

= ?

N

2

=0.1×1=0.1N

V

2

=40ml

0.2×V

1

=0.1×40

V

1

=20ml