What volume of 0.1 m h2so4 solution is needed to neutralize 40 ml of 0.2 m naoh solution?
Answers
Answered by
58
Hey dear,
● Answer -
40 ml of 0.1 m H2SO4
● Explaination -
NaOH dissociates as -
NaOH --> Na+ + OH-
Hence, it will produce
[OH] = 0.2 × 40 / 1000 moles
[OH] = 8×10^-3 moles
So We'll need same amount of H+ ions to neutralize it.
H2SO4 dissociates as -
H2SO4 --> 2H+ + (SO4)2-
Hence, it will produce
[H+] = 2 × 0.1 × x / 1000
8×10^-3 = 2 × 0.1 × x / 1000
x = 40 ml
Therefore, 40 ml of 0.1 m H2SO4 will be required.
Hope this helps you...
● Answer -
40 ml of 0.1 m H2SO4
● Explaination -
NaOH dissociates as -
NaOH --> Na+ + OH-
Hence, it will produce
[OH] = 0.2 × 40 / 1000 moles
[OH] = 8×10^-3 moles
So We'll need same amount of H+ ions to neutralize it.
H2SO4 dissociates as -
H2SO4 --> 2H+ + (SO4)2-
Hence, it will produce
[H+] = 2 × 0.1 × x / 1000
8×10^-3 = 2 × 0.1 × x / 1000
x = 40 ml
Therefore, 40 ml of 0.1 m H2SO4 will be required.
Hope this helps you...
Answered by
7
Explanation:
since H2SO4 is a dibasic acid Normality =molarity*2
=0.1*2
=0.2 N
NaOH is monoacidic ' so
Normality= Molarity x
= 0.2 x 40
=8N
The value of H2SO4 required = 8/0.2N
= 40 ML
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