Question

What volume of 0.1 m NAOHwould be required to neutralise 100ml of concentrated aqueous sulphuric acid which contains 98% H2SO4 by mass. The density of concentrated sulphuric acid solution is 1.84g/ml.

Answer 1

Answer:

calculate the volume of 0.1M NaOH solution which is required to neutralize 100mL of concentrated aqueous sulphuric acid ehich contains 98% H2SO4 by mass. The density of H2SO4 is1. 84g/mL. Since concentration is given as 98% by mass, 184g of the solution will contain 0.98 * 184 = 180.32g of H2SO4.

Explanation:

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Answer 2

Answer:

Since concentration is given as 98% by mass, 184g of the solution will contain 0.98 * 184 = 180.32g of H2SO4. Therefore, 180.32g constitutes 1.84 moles. Therefore, to get 147g of NaOH, we need to take 147/4 = 36.76 litres of 0.1M NaOH. Hence, 36.76 litres of 0.1M NaOH is required

Explanation:

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