what volume of 0.1243 M KOH is required to neutralize 25.00ml of 0.1540M H2SO4?
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Answer:
62 ml approx
By Gram equivalent
M1× nf × V1 = M2× nf ×V2
V1 = M2 ×nf2 × V2/M1× nf1
V1 = 7.7/.1243
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