Question

What volume of 0.1m ca(oh)2 is sufficientto neturalise 100 ml solution containing 0.1 n hcl and 0.1 n h2so4?

Answer 1

n-factor of Ca(OH)₂ = 2 (because when dissociated, it gives out 2 OH⁻ ions)

Normality = Molarity x n-factor = 0.1 x 2 = 0.2 = N₁

Volume of Ca(OH)₂ required = V₁

Normality of HCl = 0.1 = N₂

Volume of HCl = 10ml = V₂

Using the formula N₁V₁ = N₂V₂

(0.2)(V₁) = (0.1)(10)

V₂ = 1/0.2

V₂ = 5ml

Thus, 5ml of 0.1M Ca(OH)₂ is required to neutralise 10ml of 0.1N HCl.

Hope it helps!!

Answer 2

Dear Student,

◆ Answer -

Volume of Ca(OH)2 = 50 ml

◆ Explanation -

Both HCl and H2SO4 solution have same normality. So whatever be the individual proportion, average normality will be same.

# Given -

N1 = 0.1 N

V1 = 100 ml = 0.1 L

m2 = 0.1 m

# Solution -

Normality of Ca(OH)2 solution is calculated by -

Normality = basicity × molarity

N2 = 2 × 0.1

N2 = 0.2 N

For complete neutralization of acid,

N1.V1 = N2.V2

0.1 × 0.1 = 0.2 × V2

V2 = 0.01 / 0.2

V2 = 0.05 L

V2 = 50 ml

Therefore, 50 ml of Ca(OH)2 is required for neutralizing given acidic mixture.

Thanks dear.