what volume of 0.20MH2so4 is required to produce 34.0 g of H2s by the reaction :
8ki + 5H2so4 --------> 4k2Hso4 + 4i2 + H2s +H20.?
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1 mole of H2S = 5 mol of H2SO4.
so ,
34 / 34 = 1 mole of H2S equivalent 5 mole of H2SO4.
since ,
0.20 × V = 5
V = 5 / 0.20
V = 25 litre.
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1 mole of H2S = 5 mol of H2SO4.
so ,
34 / 34 = 1 mole of H2S equivalent 5 mole of H2SO4.
since ,
0.20 × V = 5
V = 5 / 0.20
V = 25 litre.
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