what volume of 0.45M h3po4 is needed to neutralise 60ml of 0.60N naoh solution(assume that there is complete ionisation of acid and base)
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Answer:26.6
Explanation:
We have formula V1M1=V2M2
We have to find V1
M1=0.45
V2=60ml or 0.06 litre
N2=0.6N= 0.2M as the basicity is 3
V1 x 0.45=0.2 x 60 (simplify further)
=26.6ml
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