Question

What volume of 0.5M acid is needed to neutralize 200ml of 4M base?​

Answer 1

Answer:

Explanation:

Use formula

V1S1=V2S2

Where V1 = volume of hcl

S1= strength of hcl( given 0.5M)

V2=volume of NaOH ( 20 ml)

S2 = strength of NaOH( 0.5M)

So, V1= 0.5*20/ 0.5= 20 ml

Answer 2

Answer: 1600mL

Explanation:

Data:

M1=0.5M

M2=4M

V2=200mL

V1=?

Solution:

M1V1=M2V2

0.5xV1 = 4x200

V1 = 4x200/0.5

V1 = 800/0.5

V1 = 1600mL