Question

What volume of 0.5M HCL is needed to neutralize 90mL of 0.5 NaOH

Answer 1

Answer:

Clearly there is a 1:1 equivalence, and as a first step we calculate the number of moles of hydrochloric acid:

45.0×10−3⋅L×0.400⋅mol⋅L−1 = 1.80×10−2⋅mol hydrochloric acid.

We find an equivalent molar quantity of sodium hydroxide:

1.80×10−2⋅mol0.500⋅mol⋅L−1×103⋅mL⋅L−1 = 36.0⋅mL.

This volume is reasonable, in that it is LESS than the volume of the less concentrated acid.

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