Question

What volume of 0.742 M Na CO, solution contains 44.9 of NaCO3​

Answer 1

Answer:

90

Explanation:

The molar mass of sodium carbonate is 106 g/mol.

2.65 g of sodium carbonate corresponds to

106

2.65

=0.025 moles

Molar concentration will be the ratio of the number of moles of sodium carbonate to the volume of solution. It will be

0.250

0.025

=0.1 M.

0.1 M solution is diluted to 0.001 M

MV=M

′

V

′

0.1×10=0.001×(10+X)

10+X=1000

X=1000−10=990 ml

Hence, the value of X is 90.