Question

What volume of 0.8 M AICI, solution should be mixed with 50 ml of 0.2M CaCl, solution to get solution of
chloride ion concentration equal to 0.6M?
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Answer 1

Answer:

Explanation:

the molarity of Cl^-1 in aluminium chloride is 3 x 0.2 = 0.6 

the molarity of chloride ion in MgCl2 = 2 x 0.1 = 0.2 

 after mixing the volume changes =( M1V1 + M2V2) / V1+ V2 = 500x0.6 + 500 x 0.2 / 1000 = 0.4

Answer 2

Answer:

1 mole of CaCl2 has 2 moles of Cl-

5 moles of CaCl2 has = 2x5 = 10 moles of Cl-

1 mole of MgCl2 has 2 moles of Cl-

5 moles of MgCl2 has = 2x5 = 10 moles of Cl-

Total number of moles of Cl- = 10 + 10

                                             = 20 moles

The concentration of Cl ions in the solution in terms of molarity

                                                = 20M