What volume of 1.0 M HCI do you need to obtain 250 mL of 0.1 M HCI? Dilute the 1.0 M HCI prepared in the previous experiment to 250 mL of 0.1 M HCI using the answer to the question above.
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Answered by
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Explanation:
I guess your 37%HCL has 12 mol/L?
--> 1kg x 0,37=370gHCL
370g/36,5g/mol=10,137mol/kg
1l=1,185kg
10,137 x 1,185kg/l =12,0mol/l
(x/ml(12mol HCL)*12mol/L)/100ml=0,025mol/L
x=
I hope this helps?!
Answered by
0
Answer:
i dont know sorry
Explanation:
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