Question

What volume of 1.0moldm of sodium hydroxide will neutralize 4.0dm3 of 0.50moldm3 of HCl

Answer 1

Answer:

SORRY I DONT KNOW THE ANSWER

Explanation:

Answer 2

Answer:

Explanation:The amount in moles of a solute in a given volume of solution can be calculated if the concentration of the solution is known. The mass of solute can then be calculated.

Rearranging the equation for concentration below:

Concentration~in~mol/dm^{3}=\frac{amount~of~solute~in~mol}{volume~in~dm^{3}}

Gives:

Amount of solute in mol = concentration in mol/dm3 × volume in dm3

Example

Calculate the amount of sodium hydroxide, NaOH, in 25.0 cm3 of solution of concentration 0.1 mol/dm3.

Converting the volume from cm3 to dm3, 25.0 cm3 = 25.0 ÷ 1000 = 0.025 dm3.

Amount of NaOH in mol = concentration in mol/dm3 × volume in dm3

= 0.1 mol/dm3 × 0.025 dm3

= 0.0025 mol

Calculating masses from concentration and volume

If the amount in mol of a solute in a given volume of solution is known, its mass can also be calculated.

Question

For the example above, calculate the mass of NaOH in 25.0 cm3 of solution. (Mr = 40 g

Mass = amount × relative formula mass

= 0.0025 × 40

= 0.1 g