Question

What volume of 10 M HCl and 3 M HCl should be mixed to get 1L of 6 M HCl

solution?​

Answer 1

Answer:Suppose that the volume of 10M HCl (V1) = x L

So, Volume of 3M HCl to make 1l 3m hcl (V2)(1-x) L

Let us take M1 = 10M and M2 = 3M,  

We know that, Molarity of a mixture equation : (M1V1 + M2V2) / (V1 + V2) = M3  

[10x + 3(1-x)] / 1 = 6

10x - 3x  + 3 = 6  

7x =  3  

x = 3 / 7 = 0.43

Therefore, Volume of 10M HCl = 0.43L and Volume of 3 M HCl = 1-0.43 = 0.57 L

Explanation: