What volume of 10% (w/v) solution of Na2co3, will be required to neutralise 100ml of hcl solution containing 3. 65 g of HCI?
Using M1V1=M2V2 formula
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lakshmimaha683:
I have asked for answer using M1V1 =M2V2 formula method... please provide that
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Answer:
0.38M
Explanation:
We know that,
M1V1 + M2V2 = M3V(1+2) {where M denotes molarity and V denotes volume}
as, sum of number of moles in individual solution is equal to number of moles in the mixture.
0.5(20) + 0.3(30) = M3(20+30)
19/50 = M3
0.38=M3
hence the molarity of the resulting solution is 0.38
Thanks!
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