what volume of 10M HCL and 3M HCL should be mixed to get 1 litre of 6 M HCL
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Answer:Suppose the volume of 6M HCl required to prepare 1 L of 3M HCl = x L. Volume of 2M HCl required = 1 - x L. Apply molarity equation. M1V1 + M2V2 = M3V3.
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