Question

what volume of 10m hcl and 3m hcl should be mixed to get 1 l of 6m hcl solution?

Answer 1

Suppose that the volume of 6M HCl (V1) = x L
So, Volume of 2M HCl required to make 1L of 3M HCl (V2) = (1-x) L
Let us take M1 = 6M and M2 = 2M, 
We know that, Molarity of a mixture equation :
(M1V1 + M2V2) / (V1 + V2) = M3
[6x + 2(1-x)] / 1 = 3
6x - 2x  + 2 = 3
4x = 1 x = 1/4 = 0.25 L
Therefore, Volume of 6M HCl = 0.25L and Volume of 2 M HCl = 1-0.25 = 0.75 L

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