Question

What volume of 10M HCl and 3M HCl should be mixed to obtain 1L of 6M HCl
solution?

Answer 1

Answer:

Suppose the volume of 6M HCl required to prepare 1 L of 3M HCl = x L

Volume of 2M HCl required = 1 - x L

Apply molarity equation

M1V1 + M2V2 = M3V3

6 � (x) + 2 ( 1-x) = 3 x 1

6x + 2 - 2x = 3

4x +2 = 3

4x = 3 - 2

4x = 1

x = 1/4 = 0.25 L

so volume of 6M HCl required = 0.25 L

  volume of 2M HCl required = 1 - 0.25 = 0.75 L

Explanation: