Question

What volume of 10m hcl and 3m hcl should be mixed to obtain 1l of 6m hcl solution?

Answer 1

Suppose that the volume of 10M HCl (V1) = x L
So, Volume of 3M HCl to make 1l 3m hcl (V2)(1-x) L
Let us take M1 = 10M and M2 = 3M, 
We know that, Molarity of a mixture equation : (M1V1 + M2V2) / (V1 + V2) = M3 
[10x + 3(1-x)] / 1 = 6
10x - 3x  + 3 = 6 
7x =  3 
x = 3 / 7 = 0.43
Therefore, Volume of 10M HCl = 0.43L and Volume of 3 M HCl = 1-0.43 = 0.57 L

Answer 2

Answer: 0.57 L and 0.43 L

Explanation: