Question

what volume of 10n and 2n hcl should be mixed to obtain 4 litres of 5n hcl gas

Answer 1

Given:

N1 = 10 N

N2 = 2 N

N = 5 N

V = 4 L

To Find:

Volume of HCl required to get the desired composition.

Calculation:

- Let the equal volume of 10 N and 2 N HCl be V'.

- Using Normality equation, we get:

N1 × V' + N2 × V' = N × V

⇒ (10 + 2) × V' = 5 × 4

⇒ 12 V' = 20

⇒ V' = 20/12

⇒ V' = 1.67

- So 1.67 L each of 10 N and 2 N HCl should be mixed to get the required HCl.