Question

What volume of 12 N hcl and 3N hcl must be mixed to get 6N hcl?

Answer 1

Answer:hno3 h2so4

Explanation:

Answer 2

Answer:

Best Answer

Let x be the number mL of 10M HCl needed.

Assuming additive volumes, then 1000 - x is the number of mL of 3M HCl needed.

Then:

10x + 3(1000 - x) = 6 (1000)

Solve for x using algebra:

x = 3000 / 7 ≈ 429 ml of 10M HCl

1000 - 429 = 571 ml of 3M HCl