Question

What volume of 2n hcl be taken to form 500ml n+10 solution of hcl?

Answer 1

Let us suppose V1 mL of 2N HCl and V2 mL of 5N HCl solutions give the maximum volume of 3N solution. Then, 2*V1+5*V2 = 3*(V1+V2)
V1= 2*V2.
Since maxm value of V1 = 500 mL, hence maxm value of V2 = 250 mL.