what volume of 3 molar HNO3 is needed to oxidize 8g of Fe2+ to Fe3+ ? HNO3 --> NO
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HNO3 + 3 Fe2+ --------> 3 Fe3+ +side products
77 g 168 g
168 g of Fe2+ forms HNO3 = 77g
8 g of Fe2+ forms HNO3 = 77x8/168
= 3.67 g
molarity = 3M
molarity = w x 1000/Mx V
3 = 3.67 x 1000/77x V
V= 15.88 ml
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