What volume of 6.00 M HNO3 solution is needed to prepare 1500 mL of 0.180 M HNO3 solution?
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Answer:
Explanation:
M1V1=M2V2
6× V1=0.18 × 1500
V1= 0.18×1500/6
V1 = 0.03× 1500
V1 = 45 ml
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