Question

what volume of 63% HNO3 having density 1.4 gml is required to prepare 200 ml of 0.7 M HNO3 solution​

Answer 1

Explanation:

• concentration of a solution is the amount of moles of the salute present in 1 litre of the solution
• concentration of the solution = no of moles of solute/ Volume of solute (ML)
• Given-concentrated NHO3 is 63%
• weight density of NHO3 IS 1.4 G/ML
• Moles mass of NHO3=63G/ML
• 63 gram of NHO3 is present in 100 gram of solution
• No of moles of NHO3 in solution =63g/63gml= 1mole
• volume of solution =no of moles of solute /volume in solution(inL)=1mole/0.71428L=14M
• Volume of NHO3 solution needed to produce =1.2M of 250 ML

is

M1V1=M2V2

V1=M2V2/M1

V1=1.2M*250ML

V1=21.4ML

Answer 2

Answer:

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