Question

What volume of 63 % HNO3(wt/wt) having density 1.4 g m/L is required to prepare 200 ml of 0.7M HNO3 Solution is
1)15 ml
2)10 ml
3)20 ml
4)40 ml

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Answer 1

see the attachment for the answer

Answer 2

Given Data

• d = 1.4 g m/L (Density)

• wt/wt % = 63%

• V2 = 200ml (Volume)

• M2 = 0.7

Formula applied

M = density × w/w% of Solute × 10 /Gram molecular weight

Now ,

Putting the above values in the given formula

We get ,

M = 3.63× 10 ×1.4 / 63

Upon solving ,

We get

M = 14 .

As we know

M1V1 = M2V2

14 × V1 = 0.7 × 200

V1 = 0.7 × 200 / 14

= 7× 200 / 10 × 14

= 200 / 10 × 2

V1 = 10 ml

Answer

Option 2) 10 ml