Question

What volume of 96%by weight sulphuric acid of density 1.83gm/ml is required to prepare 2 litres of 3M sulphuric acid?

Answer 1

Answer:

Here, 96 g sulphuric acid is present in 100 g of solution (96% by weight). Hence, 960 g sulphuric acid is present in 1 liter solution. Therefore, molarity of the solution will be 960/98.08 = 9.78 M. To prepare 2 liter of 3 M solution, you will need (3/9.78)*2000 = 613.5 ml of sulphuric acid and the rest will be water.

Answer 2

Explanation:

Here, 96 g sulphuric acid is present in 100 g of solution (96% by weight). Hence, 960 g sulphuric acid is present in 1 liter solution. Therefore, molarity of the solution will be 960/98.08 = 9.78 M. To prepare 2 liter of 3 M solution, you will need (3/9.78)*2000 = 613.5 ml of sulphuric acid and the rest will be water.

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