What volume of a 0.125M NiCl2 solution contains 3.25g NiCl2?
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Answer:201L
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- The volume of NiCl2 can be calculated using the formula of molarity.
- Moles of solute per unit volution of the solution is defined as molarity.
Molarity (M) = n/V, where
n= no. of moles of the solute.
V= volume of the solution in liters.
- In the question, we know
Molar mass of NiCl2= 129
Molarity of NiCl2= 0.125M
n = 3.25/129 = 0.02519
M = n/V
0.125 = (0.02519/V)×1000
V = 201 L
Hence, the volume of NiCl2 is 201 L.
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