Question

what volume of a 5M H2 SO4 solution should be added to a 150 mL of 1. M H2SO4 solution to obtain a solution of sulphuric acid of molarity 2.5?​

Answer 1

Answer:

V = 90.

Explanation:(5 × V) + (1 × 150) = (150 + V) × 2.5

Solving Above We'll Get,

5V + 150 = 375 + 2.5V

2.5V = 225

∴V = 90

SO, ADDING 90ml. OF 5M H2SO4, TO 150ml. OF 1M H2SO4 WE GET FINAL MIXTURE 250ml. OF 2.5M H2SO4.

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Answer 2

Given:

A 150 mL of 1. M H2SO4 solution.

To Find:

The volume of a 5M H2 SO4 solution should be added to a 150 mL of 1. M H2SO4 solution to obtain a solution of sulphuric acid of molarity 2.5.

Solution:

To find the volume of a 5M H2 SO4 solution should be added to a 150 mL of 1. M H2SO4 solution we will follow the following steps:

As we know,

The formula used for finding the Molarity or Normality of the resulting solution is given by:

N1V2 + N2V2 = N3V3

n1M1V2 + n2M2V2 = n3M3V3

Here,

N = normality

n = number of electrons or ions exchanged which is equal to 2 for H2SO4 because H2SO4-----> 2H+ + (SO4)2-

V is the volume used.

2×5× V1 + 2×150×1 = 2×2.5× (150+V1)

5×V1 + 150 = 375 + 2.5V1

2.5× V1 = 225

V1 = 90ml

Henceforth, the volume of a 5M H2 SO4 solution should be added to a 150 mL of 1. M H2SO4 solution to obtain a solution of sulphuric acid of molarity 2.5 is 90 ml.